幽灵资源网 Design By www.bzswh.com
集合是无序的，天生不重复的数据组合，它的作用如下：
- 去重，即：把一个列表变成集合，就去重了
- 关系测试，即：测试两组集合的交集、并集和差集等
一、集合常用方法总结
二、定义
1、语法
> name_1 = [1,2,3,4,7,8,7,10]
#把列表转换为集合
> name_1 = set(name_1)
#转换后，去重
> print(name_1,type(name_1))
{1, 2, 3, 4, 7, 8, 10} <class 'set'>
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.intersection(name_2)
{8, 1, 10, 3}
2、并集(union())
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.union(name_2)
{1, 2, 3, 4, 5, 7, 8, 10}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.difference(name_2)
{2, 4, 7}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出结果
> name_3.issubset(name_1)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出结果
> name_1.issuperset(name_3)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.symmetric_difference(name_2)
{2, 4, 5, 7}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_3 = [11]
> name_1 = set(name_1)
> name_2 = set(name_2)
> name_3 = set(name_3)
#有交集
> name_1.isdisjoint(name_2)
False
#无交集
> name_1.isdisjoint(name_3)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 & name_2
{8, 1, 10, 3}
2、并集(|)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 | name_2
{1, 2, 3, 4, 5, 7, 8, 10}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 - name_2
{2, 4, 7}
4、对称差集(^)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出
> name_1 ^ name_2
{2, 4, 5, 7}
5、是否是子集(<=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_3 <= name_1
True
6、是否是父集(>=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_1 >= name_3
True
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.intersection(name_2)
{8, 1, 10, 3}
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.union(name_2)
{1, 2, 3, 4, 5, 7, 8, 10}
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.difference(name_2)
{2, 4, 7}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出结果
> name_3.issubset(name_1)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出结果
> name_1.issuperset(name_3)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.symmetric_difference(name_2)
{2, 4, 5, 7}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_3 = [11]
> name_1 = set(name_1)
> name_2 = set(name_2)
> name_3 = set(name_3)
#有交集
> name_1.isdisjoint(name_2)
False
#无交集
> name_1.isdisjoint(name_3)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 & name_2
{8, 1, 10, 3}
2、并集(|)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 | name_2
{1, 2, 3, 4, 5, 7, 8, 10}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 - name_2
{2, 4, 7}
4、对称差集(^)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出
> name_1 ^ name_2
{2, 4, 5, 7}
5、是否是子集(<=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_3 <= name_1
True
6、是否是父集(>=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_1 >= name_3
True
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_1 = [1,2,3,4,7,8,7,10] > name_3 = [1,2,3,4] > name_1 = set(name_1) > name_3 = set(name_3) #输出结果 > name_3.issubset(name_1) True
> name_1 = [1,2,3,4,7,8,7,10] > name_3 = [1,2,3,4] > name_1 = set(name_1) > name_3 = set(name_3) #输出结果 > name_1.issuperset(name_3) True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.symmetric_difference(name_2)
{2, 4, 5, 7}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_3 = [11]
> name_1 = set(name_1)
> name_2 = set(name_2)
> name_3 = set(name_3)
#有交集
> name_1.isdisjoint(name_2)
False
#无交集
> name_1.isdisjoint(name_3)
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 & name_2
{8, 1, 10, 3}
2、并集(|)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 | name_2
{1, 2, 3, 4, 5, 7, 8, 10}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 - name_2
{2, 4, 7}
4、对称差集(^)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出
> name_1 ^ name_2
{2, 4, 5, 7}
5、是否是子集(<=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_3 <= name_1
True
6、是否是父集(>=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_1 >= name_3
True
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出结果
> name_1.symmetric_difference(name_2)
{2, 4, 5, 7}
> name_1 = [1,2,3,4,7,8,7,10] > name_2 = [1,3,5,8,10] > name_3 = [11] > name_1 = set(name_1) > name_2 = set(name_2) > name_3 = set(name_3) #有交集 > name_1.isdisjoint(name_2) False #无交集 > name_1.isdisjoint(name_3) True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 & name_2
{8, 1, 10, 3}
2、并集(|)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 | name_2
{1, 2, 3, 4, 5, 7, 8, 10}
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 - name_2
{2, 4, 7}
4、对称差集(^)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出
> name_1 ^ name_2
{2, 4, 5, 7}
5、是否是子集(<=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_3 <= name_1
True
6、是否是父集(>=)
> name_1 = [1,2,3,4,7,8,10]
> name_3 = [1,2,3,4]
> name_1 = set(name_1)
> name_3 = set(name_3)
#输出
> name_1 >= name_3
True
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 & name_2
{8, 1, 10, 3}
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 | name_2
{1, 2, 3, 4, 5, 7, 8, 10}
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#结果输出
> name_1 - name_2
{2, 4, 7}
4、对称差集(^)
> name_1 = [1,2,3,4,7,8,7,10]
> name_2 = [1,3,5,8,10]
> name_1 = set(name_1)
> name_2 = set(name_2)
#输出
> name_1 ^ name_2
{2, 4, 5, 7}
5、是否是子集(<=)
> name_1 = [1,2,3,4,7,8,10] > name_3 = [1,2,3,4] > name_1 = set(name_1) > name_3 = set(name_3) #输出 > name_3 <= name_1 True
6、是否是父集(>=)
> name_1 = [1,2,3,4,7,8,10] > name_3 = [1,2,3,4] > name_1 = set(name_1) > name_3 = set(name_3) #输出 > name_1 >= name_3 True
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
#添加已存在，不报错
> name_2.add(1)
> name_2
{8, 1, 10, 3, 5}
#添加不存在，添加一个新的数值
> name_2.add(11)
> name_2
{1, 3, 5, 8, 10, 11}
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.update([12,13,14])
#输出结果
> name_2
{1, 3, 5, 8, 10, 12, 13, 14}
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
> name_2.remove(1)
#输出
> name_2
{8, 10, 3, 5}
#删除不存在的元素，会报错
> name_2.remove(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
KeyError: 1
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2
{8, 1, 10, 3, 5}
#输出
> name_2.pop()
8
"htmlcode">
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
特别提示：用discard删除不存在的元素，不会出现报错
4、长度(len())
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> len(name_1)
7
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#结果输出
> 1 in name_1
True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_2 = [1,3,5,8,10]
> name_2 = set(name_2)
> name_2.discard(10)
#输出结果
> name_2
{8, 1, 3, 5}
#删除不存在元素，不报错
> name_2.discard(10)
> name_1 = [1,2,3,4,7,8,7,10] > name_1 = set(name_1) #结果输出 > len(name_1) 7
> name_1 = [1,2,3,4,7,8,7,10] > name_1 = set(name_1) #结果输出 > 1 in name_1 True
"htmlcode">
> name_1 = [1,2,3,4,7,8,7,10]
> name_1 = set(name_1)
#输出
> 12 not in name_1
True
> name_1 = [1,2,3,4,7,8,7,10] > name_1 = set(name_1) #输出 > 12 not in name_1 True
更多关于Python集合操作方法可查看下面的相关链接
幽灵资源网 Design By www.bzswh.com
广告合作：本站广告合作请联系QQ：858582 申请时备注：广告合作（否则不回）
免责声明：本站文章均来自网站采集或用户投稿，网站不提供任何软件下载或自行开发的软件！ 如有用户或公司发现本站内容信息存在侵权行为，请邮件告知！ 858582#qq.com
免责声明：本站文章均来自网站采集或用户投稿，网站不提供任何软件下载或自行开发的软件！ 如有用户或公司发现本站内容信息存在侵权行为，请邮件告知！ 858582#qq.com
幽灵资源网 Design By www.bzswh.com
暂无评论...
《魔兽世界》大逃杀！60人新游玩模式《强袭风暴》3月21日上线
暴雪近日发布了《魔兽世界》10.2.6 更新内容，新游玩模式《强袭风暴》即将于3月21 日在亚服上线，届时玩家将前往阿拉希高地展开一场 60 人大逃杀对战。
艾泽拉斯的冒险者已经征服了艾泽拉斯的大地及遥远的彼岸。他们在对抗世界上最致命的敌人时展现出过人的手腕，并且成功阻止终结宇宙等级的威胁。当他们在为即将于《魔兽世界》资料片《地心之战》中来袭的萨拉塔斯势力做战斗准备时，他们还需要在熟悉的阿拉希高地面对一个全新的敌人──那就是彼此。在《巨龙崛起》10.2.6 更新的《强袭风暴》中，玩家将会进入一个全新的海盗主题大逃杀式限时活动，其中包含极高的风险和史诗级的奖励。
《强袭风暴》不是普通的战场，作为一个独立于主游戏之外的活动，玩家可以用大逃杀的风格来体验《魔兽世界》，不分职业、不分装备（除了你在赛局中捡到的），光是技巧和战略的强弱之分就能决定出谁才是能坚持到最后的赢家。本次活动将会开放单人和双人模式，玩家在加入海盗主题的预赛大厅区域前，可以从强袭风暴角色画面新增好友。游玩游戏将可以累计名望轨迹，《巨龙崛起》和《魔兽世界：巫妖王之怒 经典版》的玩家都可以获得奖励。